(2-2/3y)^2+y^2=25

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Solution for (2-2/3y)^2+y^2=25 equation: 



(2-2/3y)^2+y^2=25

We move all terms to the left:

(2-2/3y)^2+y^2-(25)=0



Domain of the equation: 3y)^2!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

y^2+(-2/3y+2)^2-25=0

We multiply all the terms by the denominator


y^2*3y-25*3y-2+2)^2+(+2)^2=0

We add all the numbers together, and all the variables

y^2*3y-25*3y-2+2)^2+2^2=0

We add all the numbers together, and all the variables

y^2*3y-25*3y=0

Wy multiply elements

3y^3-75y=0

We do not support eypression: y^3

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